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author | Elizabeth Hunt <elizabeth.hunt@simponic.xyz> | 2023-11-11 13:15:59 -0700 |
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committer | Elizabeth Hunt <elizabeth.hunt@simponic.xyz> | 2023-11-11 13:15:59 -0700 |
commit | 3f1f18b149788fe69180dc2a348fd32425bb9a3f (patch) | |
tree | 582e7b773f16e54c7e4ca71de902d65316900767 /notes/Oct-16.org | |
parent | 586d8056c1c9e4bb4b8ef219babadc997559b83d (diff) | |
download | cmath-3f1f18b149788fe69180dc2a348fd32425bb9a3f.tar.gz cmath-3f1f18b149788fe69180dc2a348fd32425bb9a3f.zip |
hw6
Diffstat (limited to 'notes/Oct-16.org')
-rw-r--r-- | notes/Oct-16.org | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/notes/Oct-16.org b/notes/Oct-16.org index 656b261..1406737 100644 --- a/notes/Oct-16.org +++ b/notes/Oct-16.org @@ -42,7 +42,7 @@ Then x^* = 0 If we construct g(x) = 10x + xe^-x -Then g'(x) = 10 + (e^-x - xe^-x) \Rightarrow g'(x) = 10 + e^0 - 0 = 11 (this wouldn't converge)n +Then g'(x) = 10 + (e^-x - xe^-x) \Rightarrow g'(x) = 10 + e^0 - 0 = 11 (this wouldn't converge) However if g(x)) = x - (xe^-x), g'(x) = 1 - (e^-x - xe^-x) \Rightarrow g'(x^*) = 0 |